Find first non repeated character in a string in Java.
Given a string, find the first non-repeating character in it.
Lets see sample input and output:
Algorithm
We will use the HashMap to store the character as key and number of times it is repeated as value.
Step1:
Iterate through the String and put it in HashMap, if the character key is already present in Map, increment the count.
Step2:
Iterate the String and check against the HashMap, the first occurrence of any character in a String whose repetition count is 1 is our answer.
Java program to find first non repeated character in a String.
package com.javabypatel.string; import java.util.HashMap; import java.util.Map; public class FindFirstNonRepeatingCharacter { public static void main(String[] args) { String str = "madam"; System.out.println(getFirstNonRepeatingCharacter(str)); } private static char getFirstNonRepeatingCharacter(String str) { Map<Character, Integer> countMap = new HashMap<>(); for (int i = 0; i < str.length(); i++) { int count = countMap.get(str.charAt(i)) == null ? 1 : countMap.get(str.charAt(i)) + 1; countMap.put(str.charAt(i), count); } for (int i = 0; i < str.length(); i++) { if (countMap.get(str.charAt(i)) == 1) { return str.charAt(i); } } return '\0'; } }
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Enjoy !!!!
If you find any issue in post or face any error while implementing, Please comment.
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