Breadth First Search(BFS) Vs Depth First Search(DFS) with example in Java. DFS uses Stack while BFS uses Queue.
Given two words, startWord and endWord, and a dictionary, find the length of shortest transformation sequence from startWord to endWord. Rules: 1. Only one letter can be changed at a time. 2. Each intermediate word must exist in the dictionary.
Input startWord = CAT endWord = DOG dictionary = CAT, BAT, COT, COG, COW, RAT, BUT, CUT, DOG, WEB Output One shortest transformation is CAT –> COT –> COG –> DOG. the program should return Path and its length 4.
Let's look at few more example and better understand problem statement.
There can be many paths for reaching from startWord to endWord, but we have to find shortest path possible.
Implement Queue using One Stack in Java You are given a Stack data structure that supports standard push and pop operations. You need to implement Queue data structure using one Stack instances.
Lets understand the problem statement graphically and it will be more clear,
Implement Queue using Stack in Java You are given a Stack data structure that supports standard push and pop operations. You need to implement Queue data structure using Stack instances.
Lets understand the problem statement graphically and it will be more clear,
Implement Stack using Single Queue in Java You are given a Queue data structure that supports standard enQueue and deQueue operations. You need to implement Stack data structure using Single Queue.
Lets understand the problem statement graphically and it will be more clear,
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Lets understand the problem statement graphically and it will be more clear,
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